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Ex-1.1 Chapter-1 Completely Solved | Relation and Functions | Class 12th Maths Chapter-1

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Ex-1.1 Chapter-1 Completely Solved | Relation and Functions | Class 12th Maths Chapter-1

Ex1.1 Completely Solved Chapter1 | Relation & Function | Class 12 Math Chapter1 | Chapter1 Class12 Maths By Isha Class 12 Math Relation & Function Introduction Class - 12 Ex - 1.1 Q1 Math's (Relation & Function) NCERT CBSE Introduction to Relation & Function Class 12 Ex 1.1 Q1 Class 12 Math (Relation & Function) | Q1 Ex 1.1 Class 12 Math ...

71.9K viewsMar 9, 2025

Ex 1.1, 1 (ii) Class 12 - Given R = {(x, y): y = x 5 and x < 4}

Ex 1.1, 1 (ii) Class 12 - Given R = {(x, y): y = x 5 and x < 4}

Q) Find the domain of 𝑝(𝑥)=sin^(−1) (1−2𝑥^2 ). Hence,find the value of 𝑥 for which p(𝑥)=𝜋/6.

Q) Find the domain of 𝑝(𝑥)=sin^(−1) (1−2𝑥^2 ). Hence,find the value of 𝑥 for

Shivang Maths Academy

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#class 12 ex-1.1

#class 12 ex-1.1

YouTubeMaths Genius

1 views7 months ago

Q) If 𝑠𝑖𝑛 𝑐𝑜𝑡^(−1) (𝑥+1)]=𝑐𝑜𝑠(tan^(−1) 𝑥), 𝑡ℎ𝑒𝑛 𝑓𝑖𝑛𝑑 𝑥.#class12maths #shivang

Q) If 𝑠𝑖𝑛 𝑐𝑜𝑡^(−1) (𝑥+1)]=𝑐𝑜𝑠(tan^(−1) 𝑥), 𝑡ℎ𝑒𝑛 𝑓𝑖𝑛𝑑 𝑥.#class12maths #shivang

YouTubeShivang Maths Academy

4.3K views2 weeks ago

कक्षा 12 गणित प्रश्नावली 1.1 | NCERT | Class 12th Maths Chapter 1 Exercise 1.1 | संबंध एवं फलन | 📚🔥🔥

कक्षा 12 गणित प्रश्नावली 1.1 | NCERT | Class 12th Maths Chapter 1 Exercise 1.1 | संबंध एवं फलन | 📚🔥🔥

YouTubeTopper Study Hub

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Class 12 Maths Backlog Marathon 2026-27 | Complete Revision in One Shot | By Deepak Sir

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#class 12 ex-1.1

#class 12 ex-1.1

1 views7 months ago

YouTubeMaths Genius

Q) If 𝑠𝑖𝑛 𝑐𝑜𝑡^(−1) (𝑥+1)]=𝑐𝑜𝑠(tan^(−1) 𝑥), 𝑡ℎ𝑒𝑛 𝑓𝑖𝑛𝑑 𝑥.#class12maths #shivang

Q) If 𝑠𝑖𝑛 𝑐𝑜𝑡^(−1) (𝑥+1)]=𝑐𝑜𝑠(tan^(−1) 𝑥), 𝑡ℎ𝑒𝑛 𝑓𝑖𝑛𝑑 𝑥.#class12maths #shivang

4.3K views2 weeks ago

YouTubeShivang Maths Academy

कक्षा 12 गणित प्रश्नावली 1.1 | NCERT | Class 12th Maths Chapter 1 Exercise 1.1 | संबंध एवं फलन | 📚🔥🔥

कक्षा 12 गणित प्रश्नावली 1.1 | NCERT | Class 12th Maths Chapter 1 Exercise 1.1 | संबंध एवं फलन | 📚🔥🔥

769 views5 months ago

YouTubeTopper Study Hub

Q) Find the domain of 𝑝(𝑥)=sin^(−1) (1−2𝑥^2 ). Hence,find the value of 𝑥 for which p(𝑥)=𝜋/6.

Q) Find the domain of 𝑝(𝑥)=sin^(−1) (1−2𝑥^2 ). Hence,find the value of 𝑥 for which p(𝑥)=𝜋/6.

628 views5 days ago

YouTubeShivang Maths Academy

The simplest form of tan^(−1) [(√(1+x)−√(1−x))/(√(1+x)+√(1−x))] is (a π/4−x/ #cbsemaths #maths

The simplest form of tan^(−1) [(√(1+x)−√(1−x))/(√(1+x)+√(1−x))] is (a π/4−x/ #cbsemaths #maths

3.2K views2 weeks ago

YouTubeShivang Maths Academy

$Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths$

Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths

2K views1 week ago

YouTubeShivang Maths Academy

Q) Simplest form of tan^(−1) ((√(1+cosx)+√(1−cosx))/(√(1+cosx)−√(1−cosx))), π=x=3π/2 is#class

Q) Simplest form of tan^(−1) ((√(1+cosx)+√(1−cosx))/(√(1+cosx)−√(1−cosx))), π=x=3π/2 is#class

2K views2 weeks ago

YouTubeShivang Maths Academy

Q) If 𝑓(𝑥)={ ((𝑥^2−4𝑥−5)/(𝑥+1), 𝑥≠−1 𝑘,&𝑥=−1 is continuous at 𝑥=−1, then the value of 𝑘 i

1.3K views2 weeks ago

YouTubeShivang Maths Academy

Q) Domain of 𝑠𝑖𝑛^(−1) (2𝑥^2−3) is (A) (−1,0)∪(1,√2)(B) (−√2,−1)∪(0,1)(C) [−√2,−1]∪[1,√2](D) (−

2.2K views1 month ago

YouTubeShivang Maths Academy

Q) Find the value of a and b so that function f defined as:𝐟(𝐱)={((𝐱−𝟐)/|𝐱−𝟐| +𝐚, 𝐢𝐟 𝐱=𝟐

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YouTubeShivang Maths Academy

Class 12 Ex 1.1 Relations And Functions #shorts #youtubeshorts #viralshorts

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YouTubeCUC Kota

Ex 1.1, 1 (ii) Class 12 - Given R = {(x, y): y = x 5 and x < 4}

Q) If 2cos^(−1) 𝑥 = 𝑦,then(A) 0≤𝑦≤𝜋(B) −𝜋≤𝑦≤𝜋(C) 0≤𝑦≤2𝜋(D) −𝜋≤𝐲 ≤ 0 #shivangmathsacademy

1.5K views6 days ago

YouTubeShivang Maths Academy

Q) Check whether function f(x) defined as f(𝑥)={((|𝑥−3|)/(2(𝑥−3)), 𝑥=3 (𝑥−6)/6,𝑥≥3) Is

2.8K views2 weeks ago

YouTubeShivang Maths Academy

Q) If 𝑓(𝑥)={((1−sin^3 𝑥)/(3cos^2 𝑥), for 𝑥≠𝜋/2 𝑘, for 𝑥=𝜋/2) is continuous at 𝑥=𝜋/2, t

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YouTubeShivang Maths Academy

Q) The value of 𝑘 for which the function 𝑓(𝑥)={(𝑥^2 sin 1/𝑥, 𝑥≠0 𝑘(𝑥+1), 𝑥=0) is a continuo

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Multiplication Practice: 1s Table Facts up to 12 with Progress Chart

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